Question:

If $g(x) = 1 + \sqrt{x}$ and $f [g (x)] = 3 + \sqrt{2} x + x $ , then f(x) =

Updated On: Jul 6, 2022
  • $1 + 2x^2$
  • $2 + x^2$
  • $1 + x$
  • $2 + x$
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The Correct Option is B

Solution and Explanation

We have, $g (x) =1+ \sqrt {x} $ and $f [g (x)] = 3+ 2 \sqrt{x} + x$ ..(i) Also, $f [g(x)] = f (1+ \sqrt{x})$ ...(ii) By (i) and (ii), we get $f (1+ \sqrt{x}) = 3 + 2 \sqrt{x} + x$ Let $1+ \sqrt{x} = y$ or $x = (y - 1)^2$. $\therefore \, \, f (y) = 3 + 2 (y - 1) + (y - 1)^2$. $= 3 + 2y - 2 + y^2 - 2y + 1 = 2 + y^2$ $\therefore \, f (x) = 2 + x^2$
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Concepts Used:

Relations and functions

A relation R from a non-empty set B is a subset of the cartesian product A × B. The subset is derived by describing a relationship between the first element and the second element of the ordered pairs in A × B.

A relation f from a set A to a set B is said to be a function if every element of set A has one and only one image in set B. In other words, no two distinct elements of B have the same pre-image.

Representation of Relation and Function

Relations and functions can be represented in different forms such as arrow representation, algebraic form, set-builder form, graphically, roster form, and tabular form. Define a function f: A = {1, 2, 3} → B = {1, 4, 9} such that f(1) = 1, f(2) = 4, f(3) = 9. Now, represent this function in different forms.

  1. Set-builder form - {(x, y): f(x) = y2, x ∈ A, y ∈ B}
  2. Roster form - {(1, 1), (2, 4), (3, 9)}
  3. Arrow Representation