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if f x cases x 2 9 x 3 x 3 5 x 3 cases then f x
Question:
If f(x) =
\(\begin{cases}\frac{x^2-9}{x-3}, x≠3 \\ 5, x=3 \end {cases}\)
then f(x):
CUET (UG) - 2023
CUET (UG)
Updated On:
May 21, 2024
is continuous at x = 3
has removable discontinuity at x =3
has irremovable discontinuity at x=3
continuous at every real number
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The Correct Option is
B
Solution and Explanation
The correct option is (B):has removable discontinuity at x =3
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