Question:
If f(x) =\(\begin{cases}\frac{x^2-9}{x-3}, x≠3 \\ 5, x=3 \end {cases}\) then f(x):
If f(x) =\(\begin{cases}\frac{x^2-9}{x-3}, x≠3 \\ 5, x=3 \end {cases}\) then f(x):
Updated On: May 21, 2024
- is continuous at x = 3
- has removable discontinuity at x =3
- has irremovable discontinuity at x=3
- continuous at every real number
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The Correct Option is B
Solution and Explanation
The correct option is (B):has removable discontinuity at x =3
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