Question:
If \(f(x)=\begin{cases} \frac{1-\cos4x}{x^2} & x\ne0 \\ k & x=0 \end{cases}\) is continuous at x = 0, then the value of k is :
If \(f(x)=\begin{cases} \frac{1-\cos4x}{x^2} & x\ne0 \\ k & x=0 \end{cases}\) is continuous at x = 0, then the value of k is :
Updated On: Jun 13, 2024
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- 4
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The Correct Option is A
Solution and Explanation
The correct option is (A) :8.
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