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if f r2 r2 is a function defined as f x y cases x
Question:
If f: R
2
→R
2
is a function defined as
\(f(x,y) = \begin{cases} \frac{x}{\sqrt{x^2+y^2}}, & x\neq0,y\neq0\\ 2, & x=0,y=0 \end{cases}\)
then, which of the following is correct?
CUET (PG) - 2023
CUET (PG)
Updated On:
Mar 12, 2025
f(x,y) is continuous at origin
f(x,y) is differentiable at origin
\(\lim\limits_{(x,y)\rightarrow(0,0)}\)
f(x,y) exists and is equal to 2
f(x,y) is not continuous at origin
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The Correct Option is
D
Solution and Explanation
The correct answer is(D): f(x,y) is not continuous at origin
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