Question:

If $F$ is function such that $F (0) = 2, F (1) = 3, F (x+2) = 2F (x) - F (x+1)$ for $x \ge 0$, then $F (5)$ is equal to

Updated On: Jun 18, 2022
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The Correct Option is D

Solution and Explanation

We have,
$F(x+2)=2 F(x)-F(x+1)$ ... (i)
Putting $x=0$, we get
$F(2)=2 F(0)-F(1)$
$\Rightarrow F(2)=2(2)-3$
$\{\because F(0)=2, F(1)=3\}$
$\Rightarrow F(2)=4-3$
$\Rightarrow F(2)=1$
Putting $x=1$, in E (i), we get
$F(3) =2 F(1)-F(2)$
$=2(3)-1\{\because F(1)=3, F(2)=1\}$
$\Rightarrow F(3) =5$
Putting $x=2$, in E (i), we get
$F(4) =2 F(2)-F(3)$
$=2(1)-5 \{\because F(2)=1, F(3)=5\}$
$F(4) =-3$
Putting $x=3$, in E (i), we get
$F(5) =2 F(3)-F(4)$
$=2(5)+3\{\because F(3)=5, F(4)=-3\}$
$\Rightarrow F(5) =13$
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Concepts Used:

Relations and functions

A relation R from a non-empty set B is a subset of the cartesian product A × B. The subset is derived by describing a relationship between the first element and the second element of the ordered pairs in A × B.

A relation f from a set A to a set B is said to be a function if every element of set A has one and only one image in set B. In other words, no two distinct elements of B have the same pre-image.

Representation of Relation and Function

Relations and functions can be represented in different forms such as arrow representation, algebraic form, set-builder form, graphically, roster form, and tabular form. Define a function f: A = {1, 2, 3} → B = {1, 4, 9} such that f(1) = 1, f(2) = 4, f(3) = 9. Now, represent this function in different forms.

  1. Set-builder form - {(x, y): f(x) = y2, x ∈ A, y ∈ B}
  2. Roster form - {(1, 1), (2, 4), (3, 9)}
  3. Arrow Representation