Question:

If \( f : A \to B \) is an onto function, then

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For an onto (surjective) function, the image of the domain must be the entire co-domain. So, \( f(A) \) must equal \( B \).
  • \( f(A) \subset B \)
  • \( f(A) = B \)
  • \( f(A) \supset B \)
  • \( f(A) \neq B \)
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The Correct Option is B

Solution and Explanation

For a function \( f : A \to B \) to be onto (surjective), it must map every element in the domain \( A \) to an element in the co-domain \( B \) such that the range of \( f \) covers all of \( B \). This means that the image of \( A \), denoted by \( f(A) \), must be equal to the entire set \( B \). Thus, for \( f \) to be an onto function: \[ f(A) = B \] Therefore, the correct answer is: (B) \( f(A) = B \).
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