Question

If \( E \) is the electric field intensity between the plates of a charged parallel plate capacitor, energy stored per unit volume in it is (permittivity of free space = \( \epsilon_0 \))

• A. \( \epsilon_0 E^2 \)
• B. \( \frac{1}{2} \epsilon_0 E^2 \)
• C. \( \frac{1}{8} \epsilon_0 E^2 \)
• D. \( \frac{1}{4} \epsilon_0 E^2 \)
• E. \( \frac{1}{16} \epsilon_0 E^2 \)

Hint:

The energy density in the electric field of a parallel plate capacitor is directly proportional to the square of the electric field intensity.

Answer 1

The Correct Option is B

The energy stored per unit volume (energy density) in the electric field of a parallel plate capacitor is given by the formula:
\[ u = \frac{1}{2} \epsilon_0 E^2 \] where:
- \( u \) is the energy density,
- \( \epsilon_0 \) is the permittivity of free space,
- \( E \) is the electric field intensity.
Thus, the correct answer is (B).