Question:

If dissociation constant of acetic acid is \(1.6×10^{-5}\), the hydrolysis constant of sodium acetate is

  • \(1.25×10^{-9}\)
  • \(1.60×10^{-19}\)
  • \(0.65×10^{-5}\)
  • \(0.625×10^{-9}\)
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The Correct Option is D

Solution and Explanation

The correct option is (D): \(0.625×10^{-9}\)
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