Question:

If both the mass and radius of earth decrease by $1\%$, the value of (I) acceleration due to gravity would increase by $1\%$ (II) acceleration due to gravity would decrease by $1\%$ (III) escape velocity from earth's surface would decrease by $1 \%$ (IV) the gravitational potential energy of a body on earth's surface will remain unchanged

Updated On: Jul 5, 2022
  • (I) and (III)
  • (I) and (IV)
  • (II) and (IV)
  • (III) and (IV)
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The Correct Option is C

Solution and Explanation

If both the mass and radius of the earth decrease by $1 \%$, the value of acceleration due to gravity $g'=\frac{g\left(0.99 M_{e}\right)}{\left(0.99 R_{e}\right)^{2}} \approx 1.01 \frac{G M_{e}}{R_{e}^{2}}=1.01 g$ So, $g$ would increase by $(1.01-1) \times 100 \%=1 \%$ New escape velocity would be $v_{e}'=\sqrt{\frac{2 \times 0.99 M- G_e}{0.99 R_{e}}}$ $=\sqrt{\frac{2 G M_{e}}{R_{e}}}=v_{e}$ So, it will remain unchanged. Also gravitational potential energy $=\frac{G m\left(0.99 m_{e}\right)}{0.99 R_{e}}$ $=-\frac{G M_{e} m}{R_{e}}$ Hence, it also will remain same.
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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].