Question

If 'ABLE' is coded as "23-24-8-1", how will you code 'DARK'?

• A. 25-22-13-6
• B. 26-23-14-7
• C. 26-24-12-6
• D. 26-23-13-7

Hint:

For coding and decoding problems, analyze the position of each letter in the alphabet and apply the given operations systematically.

Answer 1

The Correct Option is B

Let's observe the pattern used to code 'ABLE':
- 'A' is the 1st letter of the alphabet. Subtract 1 to get 2(3)
- 'B' is the 2nd letter of the alphabet. Subtract 2 to get 2(4)
- 'L' is the 12th letter of the alphabet. Subtract 4 to get 8.
- 'E' is the 5th letter of the alphabet. Subtract 4 to get (1)
Now, applying the same pattern to 'DARK':
- 'D' is the 4th letter of the alphabet. Subtract 2 to get 26.
- 'A' is the 1st letter of the alphabet. Subtract 2 to get 2(3)
- 'R' is the 18th letter of the alphabet. Subtract 4 to get 1(4)
- 'K' is the 11th letter of the alphabet. Subtract 4 to get 7.
Thus, 'DARK' is coded as "26-23-14-7".
Therefore, the correct answer is \( \boxed{2} \).