The given equation is:
\[ \frac{a}{100} \times a + \frac{b}{100} \times b = \frac{2}{100} \times ab \]
Simplifying this equation step-by-step:
\[ \frac{a^2}{100} + \frac{b^2}{100} = \frac{2ab}{100} \]
Multiply both sides by 100 to eliminate the denominator:
\[ a^2 + b^2 = 2ab \]
This simplifies to:
\[ a^2 - 2ab + b^2 = 0 \]
Factoring the equation:
\[ (a - b)^2 = 0 \]
From this, we get:
\[ a = b \]
Thus, \( b \) is equal to \( a \), so \( b \) is 100% of \( a \).