Question:

If a list contains ’n’ number of elements and all the elements are by default sorted in ascending order, how many comparisons will be required during 1st pass of bubble sort to arrange the list in ascending order?

Updated On: May 28, 2025
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  • n - 1
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The Correct Option is C

Approach Solution - 1

In the Bubble Sort algorithm, during each pass, the algorithm compares adjacent elements and swaps them if they are in the wrong order. The first pass involves making comparisons across all the elements in the list except for the last one. This is because after the first pass, the largest element is guaranteed to be in its correct position at the end of the list.

Let's consider a list with 'n' elements arranged in ascending order. 

  • During the 1st pass, the algorithm will compare the 1st element with the 2nd, the 2nd with the 3rd, and so on, up to the (n-1)th with the nth element.
  • Therefore, in the 1st pass, there will be a total of (n-1) comparisons.

Thus, the number of comparisons required during the 1st pass of bubble sort on a list of 'n' elements is n - 1.

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Approach Solution -2

The number of comparisons required during the first pass of bubble sort on an already sorted list is n - 1.

Additional Context:

  • Bubble Sort Mechanics:
    • Always performs n-1 comparisons in first pass
    • Compares adjacent elements (i vs i+1)
    • No swaps occur in already sorted list
  • Optimization Potential:
    • Can terminate early if no swaps occur
    • Still requires full first pass verification
  • Example with n=4:
    • Comparisons: [0:1], [1:2], [2:3] → 3 total
    • No swaps needed for [1,2,3,4]
  • Time Complexity:
    • Best case (sorted): O(n) comparisons total
    • First pass always requires n-1 comparisons

Correct Answer: (3) n - 1.

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