If a line has the direction ratio -18,12and-4, then what are its direction cosines?
If a line has the direction ratio -18,12and-4, then what are its direction cosines?
Solution and Explanation
If a line has direction ratios of -18,12and-4,then its direction cosines are
\(-\frac{18}{\sqrt{(-18)^2}}\)+(12)2+(-4)2,\(-\frac{12}{\sqrt{(-18)^2}}\)+(12)2+(-4)2,\(-\frac{-4}{\sqrt{(-18)^2}}\)+(12)2+(-4)2
i.e.,\(-\frac{18}{22}\),\(\frac{12}{22}\),\(-\frac{4}{22}\)
\(-\frac{9}{11}\),\(\frac{6}{11}\),\(-\frac{2}{11}\)
Thus,the direction cosines are \(-\frac{9}{11}\),\(\frac{6}{11}\)and\(-\frac{2}{11}\).
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Concepts Used:
Vector Algebra
A vector is an object which has both magnitudes and direction. It is usually represented by an arrow which shows the direction(→) and its length shows the magnitude. The arrow which indicates the vector has an arrowhead and its opposite end is the tail. It is denoted as
The magnitude of the vector is represented as |V|. Two vectors are said to be equal if they have equal magnitudes and equal direction.
Vector Algebra Operations:
Arithmetic operations such as addition, subtraction, multiplication on vectors. However, in the case of multiplication, vectors have two terminologies, such as dot product and cross product.