Question:

If a is a positive integer, then the number of values of a satisfying $\displaystyle\int_0^{\pi/2}\begin{Bmatrix}a^2\left(\frac{\cos 3x}{4}+\frac{3}{4}\cos\,x\right)+a\,\sin\,x-20\,\cos\,x\end{Bmatrix}dx\leq-\frac{a^2}{3}$ is

Updated On: Jul 6, 2022
  • one
  • two
  • three
  • four.
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The Correct Option is D

Solution and Explanation

L.H.S. $=\left|\frac{a^{2}}{4}\cdot\frac{sin\,3x}{3}+\frac{3a^{2}}{4} sin\,x-a\, cos\,x-20 sin\,x\right|_{0}^{\pi /2}$ $=-\frac{a^{2}}{12}+\frac{3 a^{2}}{4}-20+a=\frac{2a^{2}}{3}+a-20$ $\therefore$ by the given condition $\frac{2a^{2}}{3}+a-20 \le\, -\frac{a^{2}}{3}$ $\Rightarrow 2a^{2}+3a-60 \le-a^{2} \Rightarrow 3a^{2}+3a-60 \le0$ $\Rightarrow a^{2}+a-20 \le\,0$ $\Rightarrow \left(a+5\right)\left(a-4\right)\le0$ $\Rightarrow -5 \le\, a \le\, 4$ Since a is a $+ve$ integer. $\therefore a=1, 2, 3,4$ $\therefore$ number of values of $a = 4$.
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Concepts Used:

Integral

The representation of the area of a region under a curve is called to be as integral. The actual value of an integral can be acquired (approximately) by drawing rectangles.

  • The definite integral of a function can be shown as the area of the region bounded by its graph of the given function between two points in the line.
  • The area of a region is found by splitting it into thin vertical rectangles and applying the lower and the upper limits, the area of the region is summarized.
  • An integral of a function over an interval on which the integral is described.

Also, F(x) is known to be a Newton-Leibnitz integral or antiderivative or primitive of a function f(x) on an interval I.

F'(x) = f(x)

For every value of x = I.

Types of Integrals:

Integral calculus helps to resolve two major types of problems:

  1. The problem of getting a function if its derivative is given.
  2. The problem of getting the area bounded by the graph of a function under given situations.