If a diploid cell is treated with colchicine then it becomes
The correct option is (A) : Triploid
Colchicine prevents the development of microtubules necessary for the growth of spindle fibers. To split the chromosomes in a parental cell into two daughter cells evenly, spindle fibers are required. The genetic material won't be disseminated to the two freshly growing cells if microtubules aren't produced. As a result, the metaphase stage will see a decrease in the production of new cells, and the diploid cell will divide into tetraploid cells with four chromosomes instead of two.
List - I | List – II | ||
A. | Cells are metabolically active and proliferate | i. | \(G_2 phase\) |
B. | DNA replication takes place | ii. | \(G_1 phase\) |
C. | Proteins are synthesised | iii. | \(G_0 phase\) |
D. | Quiescent stage with metabolically active cells | iv. | S phase |
List - I | List – II | ||
A. | Chiasmata formation | i. | Pachytene |
B. | Crossing over | ii. | Diakinesis |
C. | Synaptonemal complex formation | iii. | Diplotene |
D. | Terminalisation of chiasmata | iv. | Zygotene |
List - I | List – II | ||
A. | Residual Volume | i. | Maximum volume of air that can be breathed in after forced expiration |
B. | Vital Capacity | ii. | Volume of air inspired or expired during normal respiration |
C. | Expiratory Capacity | iii. | Volume of air remaining in lungs after forcible expiration |
D. | Tidal Volume | iv. | Total volume of air expired after normal inspiration |
List I | List II | ||
---|---|---|---|
A | Robert May | I | Species-Area relationship |
B | Alexander von Humboldt | II | Long term ecosystem experiment using out door plots |
C | Paul Ehrlich | III | Global species diversity at about 7 million |
D | David Tilman | IV | Rivet popper hypothesis |
The sequence of growth and division of a cell, and consists of a series of biological processes, particularly the resting phase (G0), the interphase (G1, S, G2), and cell division (i.e. mitosis and cytokinesis)