Step 1: Use the given probabilities to find \( P(A) \).
We are given:
\( P(A \cap B) = \frac{1}{3} \),
\( P(A \cup B) = \frac{5}{6} \),
\( P(B) = \frac{1}{2} \).
Use the formula for the union of two events:
\[
P(A \cup B) = P(A) + P(B) - P(A \cap B).
\]
Substitute the given values:
\[
\frac{5}{6} = P(A) + \frac{1}{2} - \frac{1}{3}.
\]
Solve for \( P(A) \):
\[
\frac{5}{6} = P(A) + \frac{3}{6} - \frac{2}{6},
\]
\[
\frac{5}{6} = P(A) + \frac{1}{6},
\]
\[
P(A) = \frac{5}{6} - \frac{1}{6} = \frac{4}{6} = \frac{2}{3}.
\]
So, \( P(A) = \frac{2}{3} \).
Step 2: Check for independence.
Two events \( A \) and \( B \) are independent if:
\[
P(A \cap B) = P(A) \cdot P(B).
\]
Compute \( P(A) \cdot P(B) \):
\[
P(A) \cdot P(B) = \frac{2}{3} \cdot \frac{1}{2} = \frac{2}{6} = \frac{1}{3}.
\]
The given \( P(A \cap B) = \frac{1}{3} \), which matches:
\[
P(A \cap B) = P(A) \cdot P(B).
\]
Thus, \( A \) and \( B \) are independent.
Step 3: Check other properties to confirm.
Mutually exclusive: Events are mutually exclusive if \( P(A \cap B) = 0 \). Here, \( P(A \cap B) = \frac{1}{3} \neq 0 \), so they are not mutually exclusive.
Dependent: Events are dependent if they are not independent. Since \( P(A \cap B) = P(A) \cdot P(B) \), they are not dependent.
Exclusive: This term is ambiguous but often means mutually exclusive, which we already ruled out.
Step 4: Evaluate the options.
(1) Independent: Correct, as \( P(A \cap B) = P(A) \cdot P(B) \). Correct.
(2) Dependent: Incorrect, as the events are independent. Incorrect.
(3) Mutually exclusive: Incorrect, as \( P(A \cap B) \neq 0 \). Incorrect.
(4) Exclusive: Incorrect, assuming it means mutually exclusive. Incorrect.
Step 5: Select the correct answer.
The events \( A \) and \( B \) are independent, matching option (1).