Step 1: Define the sets \( A \) and \( B \).
\[ A = \{x : x \text{ is an even number less than 10}\}. \]
The even numbers less than 10 are \( 2, 4, 6, 8 \). Thus:
\[ A = \{2, 4, 6, 8\}. \]
\[ B = \{x : x \text{ is a prime number less than 10}\}. \]
The prime numbers less than 10 are \( 2, 3, 5, 7 \). Thus:
\[ B = \{2, 3, 5, 7\}. \]
Step 2: Find the intersection \( A \cap B \).
The intersection \( A \cap B \) contains all elements that are common to both \( A \) and \( B \). Comparing the elements of \( A \) and \( B \):
\[ A = \{2, 4, 6, 8\}, \quad B = \{2, 3, 5, 7\}. \]
The only common element is \( 2 \). Thus:
\[ A \cap B = \{2\}. \]
Step 3: Find \( n(A \cap B) \).
The number of elements in \( A \cap B \) is:
\[ n(A \cap B) = 1. \]
Final Answer: The value of \( n(A \cap B) \) is \( \mathbf{1} \), which corresponds to option \( \mathbf{(2)} \).