We are given the equation: \[ -75 = 9a + b \] where \(0 \leq b < 9\), and \(a\) and \(b\) are integers.
Rearrange the equation to express \(b\): \[ b = -75 - 9a \] Now, we will substitute different integer values for \(a\) such that \(0 \leq b < 9\). 1. If \(a = -9\): \[ b = -75 - 9(-9) = -75 + 81 = 6 \] Thus, when \(a = -9\), \(b = 6\), which satisfies \(0 \leq b < 9\).
The correct option is (D): \(6\)
If the roots of the quadratic equation \( ax^2 + bx + c = 0 \) are real and equal, then: