A triangle's centroid is the location inside the triangle where all of its medians meet or cross. Straight lines that connect a vertex to its opposite side and divide that side into two equal half are called medians. The triangle is divided into smaller, equal-sized triangles using a median as well. There are four locations when a triangle is concurrent.
Orthocentre
Incentre
Circumcentre
Centroid
A triangle's centroid is always found inside the triangle's perimeter.
The centroid of the triangle is shown by point G in this instance. The centroid of a triangle always resides inside the triangle's perimeter, just like the incentre does. To get the centroid's coordinates, the section formula of coordinate geometry is used. A triangle's centroid, which coincides with its medians, always rests on a median and splits it 2:1. The centroid theorem refers to this.
The relative midpoints of the triangle's sides are denoted by D, E, and F. The triangle ABC's centroid is labeled G.
Following is a discussion of the characteristics of a triangle's centroid:
The coordinates of the three vertices of the triangle ABC are A(x1, y1), B(x2, y2), and C(x3, y3). D, E, and F are the respective midpoints of the sides BC, AC, and AB. G is the centroid.
Then the coordinates of the centroid of the triangle ABC are given as :
A straight line is a line having the shortest distance between two points.
A straight line can be represented as an equation in various forms, as show in the image below:
The following are the many forms of the equation of the line that are presented in straight line-
Assume P0(x0, y0) is a fixed point on a non-vertical line L with m as its slope. If P (x, y) is an arbitrary point on L, then the point (x, y) lies on the line with slope m through the fixed point (x0, y0) if and only if its coordinates fulfil the equation below.
y – y0 = m (x – x0)
Let's look at the line. L crosses between two places. P1(x1, y1) and P2(x2, y2) are general points on L, while P (x, y) is a general point on L. As a result, the three points P1, P2, and P are collinear, and it becomes
The slope of P2P = The slope of P1P2 , i.e.
\(\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}\)
Hence, the equation becomes:
y - y1 =\( \frac{y_2-y_1}{x_2-x_1} (x-x1)\)
Assume that a line L with slope m intersects the y-axis at a distance c from the origin, and that the distance c is referred to as the line L's y-intercept. As a result, the coordinates of the spot on the y-axis where the line intersects are (0, c). As a result, the slope of the line L is m, and it passes through a fixed point (0, c). The equation of the line L thus obtained from the slope – point form is given by
y – c =m( x - 0 )
As a result, the point (x, y) on the line with slope m and y-intercept c lies on the line, if and only if
y = m x +c