Question:
If $200\,MeV$ energy is released in the fission of a single nucleus of ${ }_{92} U ^{235}$, how many fissions must occur per second to produce a power of $1 \,kW ?$
If $200\,MeV$ energy is released in the fission of a single nucleus of ${ }_{92} U ^{235}$, how many fissions must occur per second to produce a power of $1 \,kW ?$
Updated On: Jun 20, 2022
- $3.125 \times 10^{13}$
- $1.52 \times 10^{6}$
- $3.125 \times 10^{12}$
- $3.125 \times 10^{14}$
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The Correct Option is A
Solution and Explanation
Total energy $/ s =1000\, J$
Energy released/fission $=200\, MeV$
$=200 \times 1.6 \times 10^{-13} \,J$
$=3.2 \times 10^{-11} \,J$
$\therefore$ Number of fission $/ s =\frac{1000}{3.2 \times 10^{-11}}$
$=3.12 \times 10^{13}$
Energy released/fission $=200\, MeV$
$=200 \times 1.6 \times 10^{-13} \,J$
$=3.2 \times 10^{-11} \,J$
$\therefore$ Number of fission $/ s =\frac{1000}{3.2 \times 10^{-11}}$
$=3.12 \times 10^{13}$
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