Question

If 2\(x^2 + 2 <20\);, which of the following cannot be the value of \(x\)?

• A. 0
• B. 1
• C. 2
• D. 3

Answer 1

The Correct Option is D

To solve the inequality 2\(x^2 + 2 <20\),we can simplify it:
Subtract 2 from both sides:
⇒\(2x^2 < 18\)
Divide by 2:
⇒\(x^2 < 9\)
Taking the square root of both sides gives:
⇒\(-3<x<3\)
Now, let's evaluate the options to find which cannot be the value of 
A. \(x=0\):This is within the range \(-3<x<3\)
B. \(x=1\):This is within the range\(-3<1<3\)
C. \(x=2\):This is within the range\(-3<2<3\)
D.\(x=3\):This is within the range \(3\) is not less than 3
The value of \(x\) that cannot satisfy the inequality.
So the correct option is (D):3