Question

If 15^th November of 2002 was Wednesday, what will be the day on 27^th October of 2003?

• A. Wednesday
• B. Thursday
• C. Friday
• D. Saturday

Hint:

For day calculations over dates, sum days between dates and use modulo 7 to cycle through the week.

Answer 1

The Correct Option is D

Step 1: Calculate the total number of days from 15^th November 2002 to 27^th October 2003.
Break into two parts:
a) From 15 November 2002 to 31 December 2002:
November has 30 days, so days remaining in November after 15th: \(30 - 15 = 15\) days
Add December days: 31 days
Total days in 2002 part = \(15 + 31 = 46\) days
b) From 1 January 2003 to 27 October 2003:
January: 31
February: 28 (2003 is not a leap year)
March: 31
April: 30
May: 31
June: 30
July: 31
August: 31
September: 30
October: 27 days
Sum: \(31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 27 = 300\) days
Step 2: Total days from 15 Nov 2002 to 27 Oct 2003 = \(46 + 300 = 346\) days
Step 3: Find the day of the week for 27 Oct 2003 using modulo 7 of total days.
Calculate \(346 \mod 7\):
\(7 \times 49 = 343\) remainder \(3\)
Step 4: Given 15 Nov 2002 is Wednesday, add 3 days:
Wednesday + 3 days = Saturday
Therefore, the day on 27 October 2003 is Saturday.