Identify the product Y in the following reaction
CH4
CH3I
CH3
CH3CH
To determine the product Y, we need to consider the reaction between propane (CH3-C-CH3) and sodium hypoiodite (NaOI). This reaction involves the substitution of iodine (I) in NaOI with a part of propane (CH3) to form a new compound.
Based on the given options:
(A) CH4 (methane) - This is not the correct product as it does not involve the substitution of iodine or the formation of sodium propanoate.
(B) CH3I (iodomethane) - This is the correct product Y. It involves the substitution of an iodine atom in NaOI with a methyl group (CH3) from propane.
(C) CH3 (methyl radical) - This is not the correct product as it represents a free radical, which is highly reactive and unstable.
(D) CH3CH (ethyl radical) - This is not the correct product as it represents another free radical, not formed in the given reaction.
Therefore, the correct product Y in the given reaction is option (B) CH3I (iodomethane).