BF₃ is a planar molecule with B-F bonds arranged symmetrically. The dipole moments of the B-F bonds cancel each other, resulting in a zero dipole moment for the molecule. Thus, option (1) is false.
In NF₃, fluorine is more electronegative than nitrogen, and the dipoles do not cancel, so NF₃ has a non-zero dipole moment.
NH₃ also has a non-zero dipole moment, but NF₃ has a greater dipole moment due to the greater electronegativity of fluorine. Thus, option (2) is true.
The carbonate ion (CO₃²⁻) has three resonance structures with equal contribution, so option (3) is true.
The ozone molecule (O₃) has two major resonance structures, so option (4) is true.
The correct answer is:
Option (4): Three canonical forms can be drawn for the CO₃²⁻ ion.
Major products A and B formed in the following reaction sequence , are
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A : The potential (V) at any axial point, at 2 m distance(r) from the centre of the dipole of dipole moment vector
\(\vec{P}\) of magnitude, 4 × 10-6 C m, is ± 9 × 103 V.
(Take \(\frac{1}{4\pi\epsilon_0}=9\times10^9\) SI units)
Reason R : \(V=±\frac{2P}{4\pi \epsilon_0r^2}\), where r is the distance of any axial point, situated at 2 m from the centre of the dipole.
In the light of the above statements, choose the correct answer from the options given below :
The output (Y) of the given logic gate is similar to the output of an/a :