BF₃ is a planar molecule with B-F bonds arranged symmetrically. The dipole moments of the B-F bonds cancel each other, resulting in a zero dipole moment for the molecule. Thus, option (1) is false.
In NF₃, fluorine is more electronegative than nitrogen, and the dipoles do not cancel, so NF₃ has a non-zero dipole moment.
NH₃ also has a non-zero dipole moment, but NF₃ has a greater dipole moment due to the greater electronegativity of fluorine. Thus, option (2) is true.
The carbonate ion (CO₃²⁻) has three resonance structures with equal contribution, so option (3) is true.
The ozone molecule (O₃) has two major resonance structures, so option (4) is true.
The correct answer is:
Option (4): Three canonical forms can be drawn for the CO₃²⁻ ion.
Major products A and B formed in the following reaction sequence , are
The velocity (v) - time (t) plot of the motion of a body is shown below :
The acceleration (a) - time(t) graph that best suits this motion is :
List-I | List-II | ||
(A) | ![]() | (I) | ![]() |
(B) | ![]() | (II) | CrO3 |
(C) | ![]() | (III) | KMnO4/KOH, \(\Delta\) |
(D) | ![]() | (IV) | (i) O3 (ii) Zn-H2O |