Question:

Identify the compound produced by the reduction of ethanenitrile with lithium aluminium hydride:

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LiAlH$_4$ reduction rules: Nitrile $\rightarrow$ Primary amine Amide $\rightarrow$ Amine Carbon chain length remains unchanged.
  • Ethylamine
  • Ethanal
  • Propylamine
  • Methylamine
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The Correct Option is A

Solution and Explanation

Concept: Lithium aluminium hydride (LiAlH$_4$) is a strong reducing agent that reduces:
  • Nitriles (–C$\equiv$N) $\rightarrow$ Primary amines (–CH$_2$NH$_2$)
The carbon chain length remains the same during reduction.
Step 1: Identify the starting compound. Ethanenitrile = CH$_3$–C$\equiv$N It contains two carbon atoms.
Step 2: Apply reduction rule. Nitrile $\xrightarrow{\text{LiAlH}_4}$ Primary amine \[ \text{R–C}\equiv\text{N} \rightarrow \text{R–CH}_2\text{NH}_2 \]
Step 3: Write product. \[ \text{CH}_3\text{–C}\equiv\text{N} \rightarrow \text{CH}_3\text{–CH}_2\text{NH}_2 \] This is ethylamine.
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