Question:

Identify the amide which gives propan-1-amine by Hoffmann bromamide reaction.

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Hoffmann bromamide reaction reduces primary amides to primary amines with one carbon less.
Updated On: Jun 3, 2025
  • \( \mathrm{CH_3CH_2CONH_2} \)
  • \( \mathrm{CH_3CH(CH_3)CONH_2} \)
  • \( \mathrm{CH_3CH_2CH_2CONH_2} \)
  • \( \mathrm{CH_3CH_2CONHCH_3} \)
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The Correct Option is C

Solution and Explanation

- Hoffmann bromamide reaction converts a primary amide into a primary amine with one less carbon atom.
- To get propan-1-amine (3-carbon chain amine), the amide must be butanamide (\(\mathrm{CH_3CH_2CH_2CONH_2}\)) which has 4 carbons, so after loss of one carbon, the amine has 3 carbons.
- Other amides do not correspond to this product.
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