Question

Identify odd group of letters: CE, IK, SV, FH, UW

• A. sv
• B. IK
• C. uw
• D. FH

Answer 1

The Correct Option is A

 To solve this logical reasoning question, we need to identify the pattern among the given pairs of letters and determine which group breaks this pattern. Let's analyze each option.

1. Consider the pair CE.
   • C is the 3rd letter, and E is the 5th letter in the alphabetical order.
   • The difference between E and C is 2.
2. Consider the pair IK.
   • I is the 9th letter, and K is the 11th letter in the alphabetical order.
   • The difference between K and I is 2.
3. Consider the pair SV.
   • S is the 19th letter, and V is the 22nd letter in the alphabetical order.
   • The difference between V and S is 3.
4. Consider the pair FH.
   • F is the 6th letter, and H is the 8th letter in the alphabetical order.
   • The difference between H and F is 2.
5. Consider the pair UW.
   • U is the 21st letter, and W is the 23rd letter in the alphabetical order.
   • The difference between W and U is 2.

From this analysis, we can observe that all pairs except SV have a difference of 2 between their letters. The pair SV has a difference of 3, which makes it the odd one out.

Therefore, the odd group of letters is SV.