(i) Yes, except at the nodes
Yes, except at the nodes
No, 0.042 m
Explanation:
(i) All the points on the string oscillate with the same frequency, except at the nodes which have zero frequency.
All the points in any vibrating loop have the same phase, except at the nodes.
All the points in any vibrating loop have different amplitudes of vibration.
The given equation is:
y(x,t)=0.06 sin \((\frac{2\pi}{3}x)\) cos (120 πt)
For x = 0.375 m and t = 0
Amplitude= Displacement= 0.06 sin \((\frac{2\pi}{3}x)\) cos 0
= 0.06 sin \((\frac{2\pi}{3}× 0,375)×1\)
= 0.06 sin (0.25 π)=0.06 sin \((\frac{\pi}{4})\)
= 0.06× \(\frac{1}{\sqrt2}=0.042\, m\)
Two loudspeakers (\(L_1\) and \(L_2\)) are placed with a separation of \(10 \, \text{m}\), as shown in the figure. Both speakers are fed with an audio input signal of the same frequency with constant volume. A voice recorder, initially at point \(A\), at equidistance to both loudspeakers, is moved by \(25 \, \text{m}\) along the line \(AB\) while monitoring the audio signal. The measured signal was found to undergo \(10\) cycles of minima and maxima during the movement. The frequency of the input signal is _____________ Hz.
(Speed of sound in air is \(324 \, \text{m/s}\) and \( \sqrt{5} = 2.23 \)) 
Find the mean deviation about the mean for the data 38, 70, 48, 40, 42, 55, 63, 46, 54, 44.