Question:

How will you distinguish between Ethanol and Methanol using the Iodoform test?

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{Iodoform test:} Ethanol → Yellow precipitate (positive) Methanol → No precipitate (negative)
Updated On: Feb 24, 2026
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Solution and Explanation

Concept: The iodoform test is used to identify compounds containing the methyl ketone group (\(-COCH_3\)) or alcohols that can be oxidized to it. Ethanol is the only primary alcohol that gives a positive iodoform test because it can be oxidized to acetaldehyde. Procedure: Add iodine solution and sodium hydroxide (NaOH) to the given alcohol and warm gently. Observation:
  • Ethanol: Produces a yellow precipitate of iodoform (\(CHI_3\)) with a characteristic antiseptic smell.
  • Methanol: Does not produce any yellow precipitate (negative test).
Reason:
  • Ethanol is oxidized to acetaldehyde (\(CH_3CHO\)), which contains the required methyl carbonyl group and gives the iodoform reaction.
  • Methanol is oxidized to formaldehyde (\(HCHO\)), which does not contain the methyl group required for the test.
Conclusion: Thus, ethanol can be distinguished from methanol because ethanol gives a positive iodoform test (yellow precipitate), while methanol does not.
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