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how many ten digit numbers can be formed using all
Question:
How many ten-digit numbers can be formed using all the digits of 2435753228 such that odd digits appear only in even places?
CMAT - 2021
CMAT
Updated On:
Jul 30, 2024
2! 3! 5!
$(5!)^2$
$\frac{(5!)^2}{3!}$
$\frac{(5!)^2}{3!(2!)^2}$
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The Correct Option is
D
Solution and Explanation
The Correct option is (D):$\frac{(5!)^2}{3!(2!)^2}$
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