Question

How many ten-digit numbers can be formed using all the digits of 2435753228 such that odd digits appear only in even places?

• A. 2! 3! 5!
• B. $(5!)^2$
• C. $\frac{(5!)^2}{3!}$
• D. $\frac{(5!)^2}{3!(2!)^2}$

Answer 1

The Correct Option is D

The Correct option is (D):$\frac{(5!)^2}{3!(2!)^2}$