Question:
How many oxygen atoms will be present in $88\, g$ of $CO_2$
How many oxygen atoms will be present in $88\, g$ of $CO_2$
Updated On: Aug 25, 2023
- $24.08\times10^{23}$
- $6.023\times10^{23}$
- $44\times10^{23}$
- $22\times10^{24}$
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The Correct Option is A
Solution and Explanation
\(1\space mol\space of\space CO_2 = 12+32 = 44 g\)
Number of oxygen in \(1\space molecule\space of\space CO_2 = 2\)
This means than 44g of \(CO_2\) contains 2 mol oxygen
Now, 88 g of \(CO_2\) will contain \(= \frac{2}{44} \times 88 =\) 4 mol of oxygen
Now, 1 molecule \(= 6.033 \times 10^{23}\space atoms.\)
\(4\space molecules = 4 \times 6.033 \times 10^{23}\space atoms\)
\(= 24.08 \times 10^{23}\space atoms\)
Number of oxygen in \(1\space molecule\space of\space CO_2 = 2\)
This means than 44g of \(CO_2\) contains 2 mol oxygen
Now, 88 g of \(CO_2\) will contain \(= \frac{2}{44} \times 88 =\) 4 mol of oxygen
Now, 1 molecule \(= 6.033 \times 10^{23}\space atoms.\)
\(4\space molecules = 4 \times 6.033 \times 10^{23}\space atoms\)
\(= 24.08 \times 10^{23}\space atoms\)
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Chemistry is a vast subject and for understanding its significance we can take help of following points:
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There are two ways of classifying the matter:
(A) Physical Classification:
Matter can exist in three physical states:
- Solids - have definite volume and definite shape
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(B) Chemical Classification:
Based upon the composition, matter can be divided into two main types:
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