The correct answer is : 3
The photoelectric effect requires a photon with energy greater than the work function of the metal.
A photon's energy is provided by
\(E=\frac{hc}{\lambda}\)
Where,
h = Planck's constant, c = Velocity of light, λ = Wavelength
here given λ = 400 nm
Then E = \(\frac{6.6\times10^{-34}\times3\times10^8}{400\times 10^{-9}}\)
E in e.V = \(\frac{6.6\times10^{-34}\times3\times10^8}{400\times 10^{-9}\times1.6\times10^{-19}}\)
E = 3 eV
The metals Li, Na, K and Mg have a work function less than the Energy of a Photon. In the presence of light with a wavelength of 400nm, they exhibit a photoelectric Effect.
When light shines on a metal, electrons can be ejected from the surface of the metal in a phenomenon known as the photoelectric effect. This process is also often referred to as photoemission, and the electrons that are ejected from the metal are called photoelectrons.
According to Einstein’s explanation of the photoelectric effect :
The energy of photon = energy needed to remove an electron + kinetic energy of the emitted electron
i.e. hν = W + E
Where,