Question:
HI can be prepared by all the following methods, except
HI can be prepared by all the following methods, except
Updated On: Jul 6, 2022
- $\ce{PI_3 + H_2 O}$
- $\ce{KI + H_2 SO_4}$
- $\ce{H_2 + I_2 ->[pt]}$
- $\ce{I_2 + H_2S}$
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The Correct Option is B
Solution and Explanation
HI cannot be prepared by heating iodides with concentrated $ {H_2SO_4}$ because HI is a strong reducing agent and reduce $ {H_2SO_4}$ to $ {SO_2}$ and get themselves oxidised to $ {I_2}$.
$ {2HI + H_2SO_4 -> SO_2 + I_2 + 2H_2 O}$
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
- Group 15 Elements: Nitrogen family
- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family