Question

HBr reacts with \( \text{CH}_2 = \text{CH} - \text{OCH}_3 \) under anhydrous conditions at room temperature to give:

• A. \( \text{BrCH}_2 - \text{CH} - \text{OCH}_3 \)
• B. \( \text{H}_2\text{C} - \text{CH} - \text{OCH}_3 \)
• C. \( \text{CH}_3 \text{CHO} \) and \( \text{CH}_3 \text{Br} \)
• D. \( \text{BrCH}_2\text{C} \text{H}_2 \text{Br} \)

Hint:

The addition of HBr to alkenes follows Markovnikov's rule, where the proton adds to the carbon with the most hydrogen atoms.

Answer 1

The Correct Option is A

Step 1: When HBr reacts with alkenes in the presence of anhydrous conditions, it adds across the double bond.
Step 2: The product formed is a bromoether, where the Br atom adds to the carbon adjacent to the ether group.

Final Answer: \[ \boxed{\text{BrCH}_2 - \text{CH} - \text{OCH}_3} \]