Question:

Glucose when heated with \( CH_3OH \) in presence of dry HCl gas gives \( \alpha \)- and \( \beta \)-methyl glucosides because it contains:

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The formation of methyl glucosides involves the reaction of hydroxyl groups with methanol in the presence of a catalyst like HCl.
Updated On: Jan 12, 2026
  • An aldehyde group
  • A \( -CH_3 \) group
  • A ring structure
  • Five hydroxyl groups
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The Correct Option is D

Solution and Explanation

Glucose contains five hydroxyl groups, which can react with methanol in the presence of HCl to form methyl glucosides.
Final Answer: \[ \boxed{Five hydroxyl groups} \]
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