Step 1: Recall the Tollen’s reagent test.
Tollen’s reagent is an ammoniacal solution of silver nitrate ($[Ag(NH_3)_2]^+$). It is a mild oxidizing agent used to distinguish aldehydes from ketones.
Step 2: Reaction with aldehyde or glucose.
When an aldehyde (or reducing sugar like glucose) reacts with Tollen’s reagent, the aldehyde group is oxidized to a carboxylic acid, and silver ions are reduced to metallic silver (Ag).
Step 3: Observation.
This metallic silver gets deposited on the inner walls of the test tube, producing the famous “silver mirror test.”
Step 4: Analyzing the options.
- (A) Ag$_2$O: Not formed in this reaction.
- (B) Ag: Correct, metallic silver is deposited.
- (C) AgCl: Not formed here; AgCl forms when Ag$^+$ reacts with chloride ions.
- (D) Ag(NH$_3$)Cl: This is part of the reagent itself, not the product.
Step 5: Conclusion.
Hence, glucose or aldehyde reacts with Tollen’s reagent to form metallic silver.
Final Answer:
\[
\boxed{\text{(B) Ag}}
\]