Question:
Given the standard electrode potentials,
K+/K = -2.93V, Ag+/Ag = 0.80V,
Hg2+/Hg = 0.79V
Mg2+/Mg = -2.37 V, Cr3+/Cr = - 0.74V
Arrange these metals in their increasing order of reducing power.
Given the standard electrode potentials,
K+/K = -2.93V, Ag+/Ag = 0.80V,
Hg2+/Hg = 0.79V
Mg2+/Mg = -2.37 V, Cr3+/Cr = - 0.74V
Arrange these metals in their increasing order of reducing power.
K+/K = -2.93V, Ag+/Ag = 0.80V,
Hg2+/Hg = 0.79V
Mg2+/Mg = -2.37 V, Cr3+/Cr = - 0.74V
Arrange these metals in their increasing order of reducing power.
Updated On: Nov 8, 2023
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Solution and Explanation
The lower the reduction potential, the higher is the reducing power. The given standard electrode potentials increase in the order of K+ /K < Mg2+/Mg < Cr3+/Cr < Hg2+/Hg < Ag+ /Ag.
Hence, the reducing power of the given metals increases in the following order:
Ag < Hg < Cr < Mg < K
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Galvanic cells (also known as Voltaic cells)
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