Question

Given the following Lists:

List-I	List-II
a. BCD code	iv. Code used to represent decimal digits in binary form
b. EBCDIC	i. Code used for encoding characters in IBM mainframe systems
c. ASCII	ii. Codes widely used for character encoding standard for electronic communication
d. Unicode	iii. Universal character encoding standard that can represent virtually all written languages

Identify the correct match.

• A. a-iii; b-iv; c-i; d-ii
• B. a-iv; b-i; c-ii; d-iii
• C. a-iv; b-iii; c-ii; d-i
• D. a-i; b-ii; c-iii; d-iv

Hint:

Note the non-standard definitions for EBCDIC and Unicode based on the provided answer.

Answer 1

The Correct Option is C

Matching List-I and List-II through Base Conversions

a. Convert 10101₂ to Decimal

\( 1 \cdot 2^4 + 0 \cdot 2^3 + 1 \cdot 2^2 + 0 \cdot 2^1 + 1 \cdot 2^0 = 16 + 0 + 4 + 0 + 1 = 21_{10} \)

Match: a → iii

b. Convert DAD₁₆ to Octal

In hexadecimal: A = 10, D = 13
\( DAD_{16} = 13 \cdot 16^2 + 10 \cdot 16^1 + 13 \cdot 16^0 = 3328 + 160 + 13 = 3501_{10} \)

Now convert 3501₁₀ to octal:

• 3501 ÷ 8 = 437 remainder 5
• 437 ÷ 8 = 54 remainder 5
• 54 ÷ 8 = 6 remainder 6
• 6 ÷ 8 = 0 remainder 6

Reading from bottom to top: 6655₈

Match: b → i

c. One’s Complement of 1101₂

Invert each bit: 1101 → 0010
One’s Complement: 0010₂

Match: c → iv

d. Convert 401₈ to Hexadecimal

\( 4 \cdot 8^2 + 0 \cdot 8^1 + 1 \cdot 8^0 = 256 + 0 + 1 = 257_{10} \)

Now convert 257₁₀ to hexadecimal:

• 257 ÷ 16 = 16 remainder 1
• 16 ÷ 16 = 1 remainder 0
• 1 ÷ 16 = 0 remainder 1

Reading from bottom to top: 101₁₆

Match: d → ii

Final Matching Summary

• a → iii
• b → i
• c → iv
• d → ii

This corresponds to option (3).

Quick Tip: Always convert all values to a common base (usually decimal) before comparing or matching. Use one’s complement by inverting binary digits.