Question:

Given below are two statements :
A number of distinct 8-letter words are possible using the letters of the word SYLLABUS. If a word in chosen at random, then
Statement I: The probability that the word contains the two S's together is \(\frac{1}{4}.\)
Statement II : The probability that the word begins and ends with L is \(\frac{1}{28}.\)
In the light of the above statements, choose the correct answer from the options given below.

Updated On: Dec 30, 2025
  • Both Statement I and Statement II are true
  • Both Statement I and Statement II are false
  • Statement I is true but Statement II is false
  • Statement I is false but Statement II is true
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The Correct Option is A

Solution and Explanation

To solve this problem, we need to determine if both statements about probabilities in forming words from the letters of "SYLLABUS" are correct.

  1. Calculate the total number of distinct 8-letter words formed from "SYLLABUS".

    Letters in "SYLLABUS": S, Y, L, L, A, B, U, S.

    Since 'L' and 'S' are repeated, the total number of arrangements is given by:

    \(\frac{8!}{2! \times 2!}\)

    Calculating this:

    \(\frac{40320}{4} = 10080\)

  2. Check Statement I: "The probability that the word contains the two S's together is \(\frac{1}{4}\)."

    Treat the two 'S's as a single unit. Thus, we have 7 units to arrange: 'SS', Y, L, L, A, B, U.

    The number of ways to arrange these units is:

    \(\frac{7!}{2!}\)

    Calculating this:

    \(\frac{5040}{2} = 2520\)

    The probability is then:

    \(\frac{2520}{10080} = \frac{1}{4}\)

    Thus, Statement I is correct.

  3. Check Statement II: "The probability that the word begins and ends with L is \(\frac{1}{28}\)."

    Fix 'L' at both ends: L _ _ _ _ _ _ L. Now, we arrange the remaining: S, S, Y, A, B, U (6 unique letters).

    The number of ways to arrange these letters is:

    \(\frac{6!}{2!}\)

    Calculating this:

    \(\frac{720}{2} = 360\)

    The probability is then:

    \(\frac{360}{10080} = \frac{1}{28}\)

    Thus, Statement II is correct.

Conclusion: Both Statement I and Statement II are true, so the correct answer is "Both Statement I and Statement II are true".

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