Let the salary of the officer be Rs \(x\).
10% is deducted as house rent, so he is left with 90% of his salary:
\(\text{Remaining salary} = 0.9x\)
He spends 15% of the remaining salary on children's education, so he is left with 85% of this:
\(\text{After education expenditure} = 0.85 \times 0.9x = 0.765x\)
He spends 10% of the balance on clothes, so he is left with 90% of this:
\(\text{After clothes expenditure} = 0.9 \times 0.765x = 0.6885x\)
After all these expenditures, he is left with Rs 1377:
\(0.6885x = 1377\)
Solving for \(x\)
\(x = \frac{1377}{0.6885} = 2000\)
Thus, the officer's salary is Rs \(2000\).
List-I | List-II |
---|---|
(A) Confidence level | (I) Percentage of all possible samples that can be expected to include the true population parameter |
(B) Significance level | (III) The probability of making a wrong decision when the null hypothesis is true |
(C) Confidence interval | (II) Range that could be expected to contain the population parameter of interest |
(D) Standard error | (IV) The standard deviation of the sampling distribution of a statistic |