To solve the analogy FJUL : BOQQ :: LHRX : ____, we need to identify the pattern or series of transformations that occur between the first pair of terms and apply these to the second pair.
- First, examine the relationship between
FJUL and BOQQ by comparing each letter:- F to B: F is the 6th letter and B is the 2nd letter of the alphabet. The shift is -4.
- J to O: J is the 10th letter and O is the 15th letter. The shift is +5.
- U to Q: U is the 21st letter and Q is the 17th letter. The shift is -4.
- L to Q: L is the 12th letter and Q is the 17th letter. The shift is +5.
- The pattern identified is a repetitive series of transformations: -4, +5, -4, +5.
- Apply the same transformations to the second term
LHRX:- L: 12th letter. Apply -4 to get 8th letter, which is H.
- H: 8th letter. Apply +5 to get 13th letter, which is M.
- R: 18th letter. Apply -4 to get 14th letter, which is N.
- X: 24th letter. Apply +5 to get 29th letter, but since the alphabet wraps around (A-Z = 1-26), 29 is equivalent to 3rd (29-26), which is C.
Thus, applying the same transformation pattern, the sequence LHRX becomes HMNC.
The option HMNC is the correct answer.