From the following information, calculate opening and closing inventory:
Gross Profit Ratio - 25%
Revenue from operations - Rs 8,00,000
Inventory turnover ratio - 4 times
Opening inventory was 2 times of the closing inventory.
Here's how to calculate the opening and closing inventory step-by-step:
1. Calculate the Cost of Revenue (Cost of Goods Sold - COGS):
- Gross Profit = Revenue from Operations * Gross Profit Ratio
- Gross Profit = Rs. 8,00,000 * 25% = Rs. 2,00,000
- Cost of Revenue (COGS) = Revenue from Operations - Gross Profit
- COGS = Rs. 8,00,000 - Rs. 2,00,000 = Rs. 6,00,000
2. Calculate the Average Inventory:
- Inventory Turnover Ratio = Cost of Revenue / Average Inventory
- 4 = Rs. 6,00,000 / Average Inventory
- Average Inventory = Rs. 6,00,000 / 4 = Rs. 1,50,000
3. Set up Equations for Opening and Closing Inventory:
Let:
- Closing Inventory = X
- Opening Inventory = 2X (Given: Opening inventory was 2 times the closing inventory)
Therefore:
- Average Inventory = (Opening Inventory + Closing Inventory)/2
Substitute with the given value:
Rs. 1,50,000 = (2X + X)/2
Rs. 1,50,000 = (3X)/2
3X = Rs. 1,50,000 * 2
X = Rs. 3,00,000/3
X = Rs. 1,00,000
4. Calculate the Opening and Closing Inventory:
- Closing Inventory (X) = Rs. 1,00,000
- Opening Inventory (2X) = 2 * Rs. 1,00,000 = Rs. 2,00,000
Answer:
- Opening Inventory: Rs. 2,00,000
- Closing Inventory: Rs. 1,00,000
From the following Statement of Profit and Loss of Nutan Ltd. for the years ended 31st March, 2023 and 2024, prepare a Comparative Statement of Profit and Loss:
Particulars | 2022–23 (₹) | 2023–24 (₹) |
Revenue from Operations | 5,00,000 | 6,00,000 |
Other Income | 20,000 | 30,000 |
Expenses | 4,00,000 | 5,00,000 |
Tax Rate | 40% | 40% |
Calculate the Inventory Turnover Ratio of the company.
Draw a rough sketch for the curve $y = 2 + |x + 1|$. Using integration, find the area of the region bounded by the curve $y = 2 + |x + 1|$, $x = -4$, $x = 3$, and $y = 0$.
A school is organizing a debate competition with participants as speakers and judges. $ S = \{S_1, S_2, S_3, S_4\} $ where $ S = \{S_1, S_2, S_3, S_4\} $ represents the set of speakers. The judges are represented by the set: $ J = \{J_1, J_2, J_3\} $ where $ J = \{J_1, J_2, J_3\} $ represents the set of judges. Each speaker can be assigned only one judge. Let $ R $ be a relation from set $ S $ to $ J $ defined as: $ R = \{(x, y) : \text{speaker } x \text{ is judged by judge } y, x \in S, y \in J\} $.