Question

From a city population, the probability of selecting a male or smoker is \( \frac{7}{10} \), a male smoker is \( \frac{2}{5} \) and a male, if a smoker is already selected, is \( \frac{3}{5} \). Then, the probability of

• A. selecting a male is \( \frac{3}{5} \)
• B. selecting a smoker is \( \frac{3}{5} \)
• C. selecting a non-smoker is \( \frac{2}{5} \)
• D. selecting a smoker, if a male is first selected, is \( \frac{8}{5} \)

Hint:

When dealing with conditional probability, use the formula \( P(A|B) = \frac{P(A \cap B)}{P(B)} \) for accurate calculations.

Answer 1

The Correct Option is D

The probability is calculated using the basic conditional probability and the principle of inclusion and exclusion for multiple events.