Question:
\(\frac{6J}{2C}=\)
\(\frac{6J}{2C}=\)
Updated On: Apr 7, 2025
- 3Ω
- 3V
- 3A
- 3W
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The Correct Option is B
Solution and Explanation
We are given energy and charge: \[ \frac{\text{Work (Joules)}}{\text{Charge (Coulombs)}} = \text{Potential difference (Volts)} \] \[ \frac{6\ J}{2\ C} = 3\ V \]
The correct option is (B): \(3V\)
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