First, without any restrictions, there are 4 people (P, Q, R, S) and the total number of ways to arrange them in a row is: \[ 4! = 24 \, \text{ways}. \] Now, we apply the restriction that R should not be seated at the second position. The number of ways in which R can be seated in the second position is: \[ 3! = 6 \, \text{ways}, \text{because after seating R in the second position, there are 3 positions left for the remaining three people}. \] Thus, the number of seating arrangements where R is not seated at the second position is: \[ 24 - 6 = 18 \, \text{ways}. \] The correct answer is (B) 9, as there are 9 valid seating arrangements where R is not in the second position.
Final Answer: 18
The figure shows an opamp circuit with a 5.1 V Zener diode in the feedback loop. The opamp runs from \( \pm 15 \, {V} \) supplies. If a \( +1 \, {V} \) signal is applied at the input, the output voltage (rounded off to one decimal place) is:
A wheel of mass \( 4M \) and radius \( R \) is made of a thin uniform distribution of mass \( 3M \) at the rim and a point mass \( M \) at the center. The spokes of the wheel are massless. The center of mass of the wheel is connected to a horizontal massless rod of length \( 2R \), with one end fixed at \( O \), as shown in the figure. The wheel rolls without slipping on horizontal ground with angular speed \( \Omega \). If \( \vec{L} \) is the total angular momentum of the wheel about \( O \), then the magnitude \( \left| \frac{d\vec{L}}{dt} \right| = N(MR^2 \Omega^2) \). The value of \( N \) (in integer) is:
In the transistor circuit shown in the figure, \( V_{BE} = 0.7 \, {V} \) and \( \beta_{DC} = 400 \). The value of the base current in \( \mu A \) (rounded off to one decimal place) is: