Question:

Four children A, B, C and D are having some chocolates each.
A gives B as many as he already has, he gives C twice of what C already has and he gives D thrice of what D already has.
Now, D gives (\(\frac 18\))th of his own chocolates to B.
Then A gives 10% chocolates he now owns to C and 20% to B.
Finally, all of them have 35 chocolates each. What is the original number of chocolates each had in the beginning?

Updated On: Sep 2, 2024
  • A-110, B-10, C-10, D-10
  • A-90, B-20, C-20, D-10
  • A-70, B-25, C-25, D-20
  • A-125, B-5, C-5, D-5
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The Correct Option is A

Solution and Explanation

The correct option is (A): A-110, B-10, C-10, D-10.
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