Question:

For which one of the following reactions will there be a positive \(\Delta S\)?

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Entropy increases when gases are produced or number of gas moles increases. Solid \(\rightarrow\) gas reactions usually give positive \(\Delta S\).
Updated On: Jan 3, 2026
  • \(H_2O(g) \rightarrow H_2O(l)\)
  • \(H_2 + I_2 \rightarrow 2HI\)
  • \(CaCO_3(s) \rightarrow CaO(s) + CO_2(g)\)
  • \(N_2(g) + 3H_2(g) \rightarrow 2NH_3(g)\)
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The Correct Option is C

Solution and Explanation

Step 1: Understand entropy change.
Entropy increases when disorder increases.
Formation of gas molecules generally increases entropy greatly.
Step 2: Check each reaction.
(A) Gas \(\rightarrow\) liquid reduces randomness, so \(\Delta S<0\).
(B) Gas + gas \(\rightarrow\) gas, moles remain same, change small (often near zero).
(C) Solid \(\rightarrow\) solid + gas increases disorder due to gas formation, so \(\Delta S>0\).
(D) 4 moles gas \(\rightarrow\) 2 moles gas reduces randomness, so \(\Delta S<0\).
Step 3: Therefore reaction with gas production is correct.
Final Answer: \[ \boxed{CaCO_3(s) \rightarrow CaO(s) + CO_2(g)} \]
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