Question:

For the reaction $ 2{{N}_{2}}{{O}_{5}}(g)\xrightarrow[{}]{{}}4N{{O}_{2}}(g)+{{O}_{2}}(g) $ if the concentration of $ N{{O}_{2}} $ increases by $ 5.2\times {{10}^{-3}} $ M in 100 s then the rate of the reaction is:

Updated On: Jun 9, 2024
  • $ 1.3\times {{10}^{-5}}M{{s}^{-1}} $
  • $ 0.5\times {{10}^{-4}}M{{s}^{-1}} $
  • $ 7.6\times {{10}^{-4}}M{{s}^{-1}} $
  • $ 2\times {{10}^{-3}}M{{s}^{-1}} $
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The Correct Option is A

Solution and Explanation

Rate of reaction $ =\frac{1}{4}\frac{d(N{{O}_{2}})}{dt} $
= $ \frac{5.2\times {{10}^{-3}}}{4\times 100} $
$ =1.3\times {{10}^{-5}}M{{s}^{-1}} $
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Concepts Used:

Rate of a Chemical Reaction

The rate of a chemical reaction is defined as the change in concentration of any one of the reactants or products per unit time.

Consider the reaction A → B,

Rate of the reaction is given by,

Rate = −d[A]/ dt=+d[B]/ dt

Where, [A] → concentration of reactant A

[B] → concentration of product B

(-) A negative sign indicates a decrease in the concentration of A with time.

(+) A positive sign indicates an increase in the concentration of B with time.

Factors Determining the Rate of a Reaction:

There are certain factors that determine the rate of a reaction:

  1. Temperature
  2. Catalyst
  3. Reactant Concentration
  4. Chemical nature of Reactant
  5. Reactant Subdivision rate