Question:

For the linear programming problem: \[ {Maximize} \quad Z = 2x_1 + 4x_2 + 4x_3 - 3x_4 \] subject to \[ \alpha x_1 + x_2 + x_3 = 4, \quad x_1 + \beta x_2 + x_4 = 8, \quad x_1, x_2, x_3, x_4 \geq 0, \] consider the following two statements: 
S1: If \( \alpha = 2 \) and \( \beta = 1 \), then \( (x_1, x_2)^T \) forms an optimal basis. 
S2: If \( \alpha = 1 \) and \( \beta = 4 \), then \( (x_3, x_2)^T \) forms an optimal basis. Then, which one of the following is correct?

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When verifying optimal bases in linear programming, check the system of equations using Gaussian elimination or matrix methods to determine if the solution satisfies the conditions of the problem.
Updated On: Apr 9, 2025
  • S1 is TRUE and S2 is FALSE
  • S2 is TRUE and S1 is FALSE
  • both S1 and S2 are TRUE
  • neither S1 nor S2 is TRUE
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The Correct Option is B

Solution and Explanation

We need to check the two statements \( S1 \) and \( S2 \) and verify if the given solutions are optimal bases.

Step 1: Analyzing S1:

For \( \alpha = 2 \) and \( \beta = 1 \), the system of equations becomes:
\[ 2x_1 + x_2 + x_3 = 4 \quad \text{and} \quad x_1 + x_2 + x_4 = 8. \]

We can set up the corresponding augmented matrix for the system:
\[ \begin{pmatrix} 2 & 1 & 1 & 0 & | & 4 \\ 1 & 1 & 0 & 1 & | & 8 \end{pmatrix} \]
Performing Gaussian elimination, we find that \( (x_1, x_2)^T \) does not form an optimal basis. Therefore, S1 is FALSE.

Step 2: Analyzing S2:

For \( \alpha = 1 \) and \( \beta = 4 \), the system of equations becomes:
\[ x_1 + x_2 + x_3 = 4 \quad \text{and} \quad x_1 + 4x_2 + x_4 = 8. \]

Setting up the augmented matrix for this system:
\[ \begin{pmatrix} 1 & 1 & 1 & 0 & | & 4 \\ 1 & 4 & 0 & 1 & | & 8 \end{pmatrix} \]
Performing Gaussian elimination here shows that \( (x_3, x_2)^T \) indeed forms an optimal basis. Therefore, S2 is TRUE.

Thus, the correct answer is:

\[ \boxed{\text{S2 is TRUE and S1 is FALSE.}} \]
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