For the given transfer function \( G(s) = \frac{5(s+4)}{(1+4s)(1+0.25s)} \), for large values of \( \omega \), the slope of the transfer function on the Bode plot is
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Each first-order pole contributes −20 dB/decade; zeros contribute +20 dB/decade.
At high frequencies, the numerator contributes +20 dB/decade, and each of the two first-order terms in the denominator contributes −20 dB/decade each.
\[
\text{Net slope} = 20 - 20 - 20 = -40~\text{dB/decade}
\]